The most obvious instance is 1310. Any number which is a multiple of 13 more or less than this would satisfy the conditions, eg 1310 + 52 = 1362 or 1310 - 91 = 1219 etc etc.
8. For a remainder of 2 when divided by 4, they must be 10, 14, 18, ..., 98 For a remainder of 1 when divided by 3, they must be 10, 13, 16, ..., 97 The overlap is 10, 22, 34, 46, 58, 70, 82, 94 - 8 numbers
You can't have a remainder of 6 when you divide by 2! JHC!
300
506
The remainder is 8. To find the remainder when a number is divided by 9, add the digits together; if this sum has more than 1 digit, repeat until one digit remains. This digit is the remainder, unless it is 9 in which case the remainder is 0. examples: remainder 53 → 5 + 3 = 8 → remainder is 8 when 53 is divided by 9. remainder 126 → 1 + 2 + 6 = 9 → remainder is 0, ie no remainder, 126 is divisible by 9. remainder 258 → 2 + 5 + 8 = 15 → 1 + 5 = 6 → remainder is 6 when 258 is divided by 9.
-3
It is 98910.
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
8. For a remainder of 2 when divided by 4, they must be 10, 14, 18, ..., 98 For a remainder of 1 when divided by 3, they must be 10, 13, 16, ..., 97 The overlap is 10, 22, 34, 46, 58, 70, 82, 94 - 8 numbers
17
103
The simplest answer is 10124 divided by 125.
Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.
100
111
12.5
0.5714