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X²+4x+5=0
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How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
How do you solve for the problem x squared minus 10 equals 4x plus 11?
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
How do you find the sum of the roots of the equation x2 plus 5x plus 9 equals 0?
This quadratic equation has no real roots because its discriminant is less than zero.
Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?
To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.
At which points does the graph of the function y equals x2 plus 4x-12 cross the x-axis?
To determine the x-intercepts, i.e. the roots, of the equation y = x2 + 4x - 12, simply solve the quadratic equation x2 + 4x - 12 = 0.Recall that the roots of a quadratic equation Ax2 + Bx + C = 0 are given by the solution x = (-B +/- square-root (B2 - 4AC) / 2A.Plug the coefficients A=1, B=4, and C=-12 into this equation and you get.x = 4 and X = -12So the function crosses the X axis at x=4 and x=-12.Note: If the discriminant, B2 - 4AC, were zero, there would be one real root instead of two. If it were negative, there would be two complex conjugate roots.
What are the coordinates of the roots of x2 plus 4x equals 0?
x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
What are the roots of the quadratic equation x2 - 4x plus 4 equals 0?
x2-4x+4 = 0 (x-2)(x-2) = 0 x = 2 or x = 2 It has two equal roots.
What is the number and type of roots of the equation x2-4x-32 equals 0?
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
What is x2 plus 4x plus 4 equals 25?
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
If the sum of the roots of x2 3x-5x0 is added to the product of the roots?
Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.
Solve x2 - 4x - 9 equals 0 by completing the square?
x2 - 4x - 9 = 0 ∴ x2 - 4x = 9 ∴ x2 - 4x + 4 = 13 ∴ (x - 2)2 = 13 ∴ x - 2 = ±√13 ∴ x = 2 ± √13
What is the solution of x2-4x-12 is less than 0?
First consider the auxiliary equation x2 - 4x - 12 = 0 This simplifies to (x + 2)(x - 6) = 0 which has root x = -2 and x = 6 Since the coefficient of x2 is positive, the inequality is satisfied between the roots that is, -2 < x < 6
X2 - 4x equals -4?
x2 - 4x + 4 = 0 (x - 2)(x - 2) = 0 x = 2
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
How do you solve for the problem x squared minus 10 equals 4x plus 11?
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
What are solutions to the equation x2 plus 4x-9 equals 5x plus 3?
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
