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How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
How do you solve for the problem x squared minus 10 equals 4x plus 11?
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
How do you find the sum of the roots of the equation x2 plus 5x plus 9 equals 0?
This quadratic equation has no real roots because its discriminant is less than zero.
At which points does the graph of the function y equals x2 plus 4x-12 cross the x-axis?
To determine the x-intercepts, i.e. the roots, of the equation y = x2 + 4x - 12, simply solve the quadratic equation x2 + 4x - 12 = 0.Recall that the roots of a quadratic equation Ax2 + Bx + C = 0 are given by the solution x = (-B +/- square-root (B2 - 4AC) / 2A.Plug the coefficients A=1, B=4, and C=-12 into this equation and you get.x = 4 and X = -12So the function crosses the X axis at x=4 and x=-12.Note: If the discriminant, B2 - 4AC, were zero, there would be one real root instead of two. If it were negative, there would be two complex conjugate roots.
Three more than the square of a number is four times the number What is the number?
In equation form, when the number is x: x2 + 3 = 4x x2 - 4x + 3 = 0 (x - 1)(x - 3) = 0 x - 1 = 0 or x - 3 = 0 x = 1 or x = 3
