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Simplify 2q 4r 2

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NutMeg1819

Lvl 1
8y ago
Updated: 4/28/2022

The above set of three terms cannot be simplified.

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8y ago

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How do you simply 4r r?

To simplify the expression (4r \cdot r), you multiply the coefficients and combine the like terms. This results in (4r^2). Thus, the simplified form of (4r \cdot r) is (4r^2).


Use the identity below to complete the tasks:a3 + b3 = (a + b)(a2 - ab + b2)Use the identity for the sum of two cubes to factor 8q6r3 + 27s6t3.What is a What is b?

Below ^ denotes power. 8q^6r^3=(2q^2r)^3 denote as a^3 and find a=2q^2r 27s^6t^3=(3s^2t)^3 denote as b^3 and find b=3s^2t Now 8q^6r^3+27s^6t^3=a^3+b^3 = (a+b)(a^2-ab+b^2) | substitute back =(2q^2r+3s^2t)(4q^4r^2-6q^2rs^2t+9s^4t^2). Notice (2q^2r)^2=4q^4r^2 (3s^2t)^2=9s^4t^2. Hence 8q^6r^3+27s^6t^3=(2rq^2+3ts^2)(4r^2q^4-6rts^2t^2+9t^2s^4), a=2q^2r and b=3s^2t.


What is the answer to -2 equals 4r plus s solving for s?

-2=4r+s s=-4r-2 or s=-(4r+2)


How would you simplify this expression 5p times 2q divided by 4p?

5p x 2p = 10p, then 10p / 4p = 2 remainder 2


What is 2q divided by q?

2q ÷ q = 2


What is 4r r in simplest form?

4r + 4 = 5r 4r - r = 3r 4r x r = 4r^2 4r/r = 4


Why is sqrt 2 irrational?

First we will assume that sqrt(2) is rational, meaning that it can be written as a ratio of two integers say (p/q) p and q must have no common factors sqrt(2)=p/q, square both sides 2=p^2/q^2, multiply both sides by q^2 2q^2=p^2, since 2 divides by the LHS, so does the RHS, meaning that p^2 is evenand because p^2 is even, so is p itselfLet p=2r with r being an integer so that p^2=2q^2=(2r)^2=4r^ 2Since 2q^2=4r^2, q^2=2r^2Because q^2 is 2r^2, then q^2 is even, meaning q itself is evenSince p and q are even, they have a common factor of 2THEREFORE, sqrt(2) cannot be rational


How do you get -2 equals 4r plus s solving for s?

s = -2 -4r


What is the product 2 of q?

2q


What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?

Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0


How do you solve this problem 2q equals -14?

16


How do I justify with steps 8(2q)?

8(2q) = (8*2)q = 16*q = 16q.