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e2x + 2ex = 8. First, let's define z to be ex Substituting gives us the following quadratic equation:

z2+2z=8 or z2+2z-8=0

Solving for z gives us two possible zs: 2 and minus 4.

As z is a power of e, only z=2 makes sense.

Back solving we get:

ex = 2

and the answer is x=ln(2). If you substitute in the answer, you get e2ln2+2eln2=8, or 4+4=8. ln(2) ~= 0.69315.

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Q: Solve e to the power of 2x plus 2e to power of x equals 8?
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