if y = 2- x then x^2 + 2x(2 - x) = 3 ie x^2 + 4 x -2x^2 = 3 ie 4x - 3 = x^2 x^2 - 4x +3 = 0 = (x - 1)(x - 3) so x = 1 or 3 Check: y= 2 - 1 =1; x^2 = 1, 2xy = 2 x 1 x 1 = 2, 1 +2 = 3. y = 2 - 3 = -1; x^2 = 9, 2xy = 2 x 3 x -1 = -6, 9 + -6 = 3. QED.
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That equals 2xy + 3y which factors to y(2x + 3)
L = 3x + 2y
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
xy + xy = 2xy
3x2+6xy+3y2= 3(x2+2xy+y2)= 3(x+y)2