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Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
It is a mathematical equation, usually written like this: 5x - 7 + 2x = 3x - 2 + 4x
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1
The answer is 3. :p
y = 12x + 5x - 7 Since '12x' and '5x' both have the same variable, you are able to combine them. To do this you just need to add 12 + 5 to get 17. After doing this you can rewrite the equation as y = 17x - 7. You can then solve this equation for different values by plugging in a number for 'x' or 'y' or graphing the equation.
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5x+y=-7 3x+y=15 8=D
8x + 7 = 5x + 28 subtract 5x and 7 to both sides 3x = 21 divide by 3 to both sides x = 7
3x-28-5x=5x+13 Let us first solve the variables -2x-28=5x+13 Transposing -28 to Right hand side -2x=5x+13+28 -2x=5x+41 Transposing 5x to left hand side -2x-5x=41 -7x=41 equation 1 x=41/-7 x=-41/7 Hence the required answer is -41/7. You can verify it by substituting the value of x in the given equation. If Right hand side is equal to Left hand side the answer is right. Let us verify Substituting the value of x=-41/7 in the given equation1 -7(-41/7)=41 -7 X -41/7 =41 41=41 LHS=RHS Hence Verified
3x + 7 = 5x - 2Subtract 3x from each side:7 = 2x - 2Add 2 to each side:9 = 2xDivide each side by 2:x = 4.5
It is: y = -1/5x+7 that is perpendicular to y = 5x+7
Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
9x-5x=4x, 7/4=1.75, x=1.75
5x-19 = 16 5x = 16+19 5x = 35 x = 7
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You do operations to get them all on one side. Eg 5x = 7y, you would divide both sides by (y) and end up with 5x/y = 7