post an equation first.
y=3x-4 y=-2x+1
2x+7y=29 x=37-8y
10.5
x - 2y = -4 2x - y = 1 To solve this system of equations, I used matrices, and got x = 2 and y = 3.
2x - 5 = 11 2x = 11 + 5 2x = 16 2x /2 = 16 /2 x = 8
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
The solutions are: x = -2 and y = 4
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
3x-8y=-1 -2x+6y=1
1.20
y=2x+12 7x+y=24 (as there is y in both equations you can assume that the equations are equal to each other, so substitute) 7x+2x+12=30 (solve) 9x=18 x=2 (substitute into the first equation to solve for y) y=(2x2)+12 y=16
y=3x-4 y=-2x+1
2x+7y=29 x=37-8y
Here are some practice problems for systems of equations: Solve the following system of equations: 2x 3y 10 4x - y 5 Find the solution to the system of equations: 3x 2y 12 x - y 3 Determine the values of x and y that satisfy the system of equations: 5x 4y 20 2x - 3y 1 Hope these help with your practice!
x + y = 50 x - y = 16 --------------- (add the two equations to solve for x) 2x = 66 x = 33 then substitute x into one of the above equations to get y = 17
x = 4 and y = 0
To use the substitution method on a system of equations without a variable with a coefficient of 1 or -1, you first isolate one variable in one of the equations. For instance, if you have the equations (2x + 3y = 6) and (4x - y = 5), you can solve the first equation for (y), resulting in (y = (6 - 2x)/3). Next, substitute this expression for (y) into the second equation, allowing you to solve for (x). Finally, substitute the value of (x) back into one of the original equations to find the corresponding value of (y).