3y + 2y + 4 + 1 = 80
5y + 5 = 80
5y = 75
y = 15
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you can not solve this equation
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
You cannot solve one linear equation in two unknown variables.
x + 52 + 2y + 35 = 3 x + 2y = 3 - 52 -35 x + 2y = -84 Infinite number of solutions, are you sure you posted the correct equation?
2y = 4x + 4y = 2x + 2