Q: What is the sum of the first 50 numbers?

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the sum of first 50 consecutive odd numbers is 9801

The sum of the first 50 counting numbers, excluding zero, is 1,251.

sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275

Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550

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Related questions

The sum of the first 50 odd numbers is 2,500.

The sum of the first 50 even numbers is 2,550.

The sum of the first 50 natural numbers is 1,251.

the sum of first 50 consecutive odd numbers is 9801

The sum of the first 50 counting numbers, excluding zero, is 1,251.

sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275

of all the things i got is 2550

2500

The sum of the composite numbers between 1 and 50 is 936.

Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550

Why, that's just 6 times the sum of the numbers from 1 to 50 !The sum of the numbers from 1 to 50 is:1 + 50 = 512 + 49 = 513 + 48 = 514 + 47 = 515 + 46 = 51...etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.

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