The sum of the first 50 whole numbers is 1,225.
Wiki User
∙ 9y agothe sum of first 50 consecutive odd numbers is 9801
The sum of the first 50 counting numbers, excluding zero, is 1,251.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550
54
The sum of the first 50 odd numbers is 2,500.
The sum of the first 50 even numbers is 2,550.
The sum of the first 50 natural numbers is 1,251.
the sum of first 50 consecutive odd numbers is 9801
The sum of the first 50 counting numbers, excluding zero, is 1,251.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
of all the things i got is 2550
2500
The sum of the composite numbers between 1 and 50 is 936.
Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550
Why, that's just 6 times the sum of the numbers from 1 to 50 !The sum of the numbers from 1 to 50 is:1 + 50 = 512 + 49 = 513 + 48 = 514 + 47 = 515 + 46 = 51...etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.
This is the way I would do it: The sum of the 1st & 100th numbers = the sum of the 2nd & 99th numbers = the sum of the 3rd & 98th numbers all the way to the sum of the 50th & 51st numbers; each of the sums equals 200. So I would multiply 200 by 50 (10000).