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8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.

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Q: Sum of three consecutive multiples of 8 is 888 find the multiples?
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The sum of three consecutive multiples of 8 is 888 find the multiple?

The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.


What are the multiples if the sum of three consecutive multiples of 8 is 888?

Clever problem !36 x 8 = 28837 x 8 = 29638 x 8 = 304288 + 296 + 304 = 888


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