8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.
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The first 15 multiples of 888: 888, 1776, 2664, 3552, 4440, 5328, 6216, 7104, 7992, 8880, 9768, 10656, 11544, 12432, 13320 . . . ∞
The first ten multiples of 111 are 111, 222, 333, 444, 555, 666, 777, 888, 999, and 1110.
888
1776
We're not sure exactly what the question is looking for, so I made upmy own, and it leads to a fascinating investigation. I hope this is actuallywhat the questioner has in mind.The question seems to be asking: "Find seven consecutive numbers that areall composite."I did a quick investigation, and found some neat stuff. I sure hope my method was valid.-- There actually is a string of seven composite numbers less than 100.They are: 90, 91, 92, 93, 94, 95, 96.-- There are seven strings of five consecutive composite numbers, all less than 100.-- The next series of seven consecutive composites doesn't occur until 360-366.But on the way there, there are five strings of 9 composites, two strings of 11 composites,and three strings of 13 composites.-- There are no series of an even number of consecutive composites, at leastnot up to 200,000 . Wonder why that is.-- The string of 19 consecutive numbers from 888 to 906 are all composite.-- Up to 200,000, the grand-daddy is the range from 155,922 to 156,006 ...a series of 85 consecutive integers that are all composite.