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8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.

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Q: Sum of three consecutive multiples of 8 is 888 find the multiples?
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What are the multiples if the sum of three consecutive multiples of 8 is 888?

Clever problem !36 x 8 = 28837 x 8 = 29638 x 8 = 304288 + 296 + 304 = 888


The sum of three consecutive multiples of 8 is 888 find the multiple?

The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.


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