Clever problem !
36 x 8 = 288
37 x 8 = 296
38 x 8 = 304
288 + 296 + 304 = 888
The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.
If half of the sum is 90 then the full sum must be 180. The three consecutive multiples of 10 which add up to 180 are 50, 60 and 70.
45, 60, and 75
45, 60, and 75
There are no three consecutive odd integers who's sum equals 13.
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.
If half of the sum is 90 then the full sum must be 180. The three consecutive multiples of 10 which add up to 180 are 50, 60 and 70.
44
45, 60, and 75
20 + 25 + 30 = 75
45, 60, and 75
91
1422, 1431, 1440
148
No. Odd numbers can be written as the sum of consecutive integers, but some multiples of odd numbers are even.