45, 60, and 75
15 and 18
There is no "most common multiple". To find all common multiples, you start by finding the least common multiple. All other common multiples are multiples of this least common multiple.
Oh, what a happy little problem we have here! If we have three consecutive numbers, we can call them x, x+1, and x+2. When we add these together and set it equal to 175, we get 3x + 3 = 175. By solving this simple equation, we find that the three consecutive numbers are 58, 59, and 60.
There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
91
45, 60, and 75
15 and 18
8, 12, 16 & 208 + 12 = 20
To find its multiples!To find its multiples!To find its multiples!To find its multiples!
There is no "most common multiple". To find all common multiples, you start by finding the least common multiple. All other common multiples are multiples of this least common multiple.
2
Use the usual procedure to find the LEAST common multiple. Then, you can multiply that by 2, or by 3, or by 4, or by 5, etc., to get additional multiples.
111
Since they are both prime, just multiple them together (65) and find multiples of that. Common multiples of 5 and 13 are: 65*1 = 65 65*2 = 130 65*3 = 195 etc
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.