Best Answer

It is quite simple...

Let the present age of the younger brother be x

And, present age of elder brother be y

x/y=3/4 eqn1

(x+6)/(y+6)=5/6 eqn 2

Solve these equations simultaniously and u'll get the answer.

x=3y/4

6x+36=5y+30

18y/4+36=5y+30

18y/4=5y-6

18y=20y-24

-2y=-24

y=12 years , that is the present age of elder brthr

x=3(12)/4=9 years , that is the present age of the younger brthr

Usama, uxama_17@hotmail.com

Q: The ages of two brothers are in the ratio 3 is to 4 but after six years the ratio of their ages will be 5 is to 6 find their present age?

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The ages are 8 and 4

Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.

42/4 = 10.510.5*3=31.5

a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.

son is 10, father is 33

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Ages are 25 and 20, so difference = 5 years.

Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17

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The ages are 8 and 4

6:3 :) i learnt about ratios to day in maths

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It will be better if you ask this question to Sachin...

Vatha is 22 years old. Chris is 16 years old. 36/2=18 + 4 years v = 22 v + c = 36 --> 22+ c = 36 --> c = 14

Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.

There ages are now 5 and 9 respectively because and in 3 years time 2/3 of 12 = 8