One possibility is 5 x 9
9
p = 75+75+45+45=240cm a = 75 x 45 = 3375cm
If you were to fence an area that was 45 ft x 80 ft, you'd need approximately 3600 ft².
Whats 7x5? 35. That is your answer.
45 meter sq. (area = length * width)
9
15x3 Area = 3x15=45 Perimeter = 3+3+15+15 = 36 This is solved algebraically by substituting the value of the length in terms of the width 2L + 2W = 36 L = 18-W L x W = 45 and (18-W) x W = 45 gives the equation W2+18W-45 = 0 (W-15)(W-3) = 0 and the width and length are 15 and 3
This question needs a serious spell check. It then needs a serious edit to make clear what it is asking!
You multiply the width by the length to get the area. In this case the answer would be a 45 square foot garden.
there are endless possible answers to this question. the easiest way to look at this is from the following. 910 sqft / 1 foot wide = 910 feet long. 910 sqft / 10 feet wide = 91 feet long. 910 sqft / 20 feet wide = 45 1/2 feet long. 910 sqft square root = ~30.16 feet by 30.16 feet. (.16 feet is about 2 inches) Square feet = length of area times width of the area. (it does not measure the ceiling clearance so there is no need to measure height.) Hope this helped.
They are: 3 ft by 15 ft
To find the total amount of fencing material needed to enclose the garden and the path, first calculate the dimensions of the garden including the path. The garden's dimensions are 33 ft by 39 ft, and adding the 3 ft path around it increases each dimension by 6 ft (3 ft on each side). This gives new dimensions of 39 ft by 45 ft. The perimeter of the enclosed area is calculated as (2 \times (39 + 45) = 168) ft, so Joe needs 168 feet of fencing material.
Perimeter of garden: 39+45+39+45 = 168 feet
Carton dimension size : 245mm x 215mm x 310 mm = how many m3 x tatal ctn 45 ctn
height + width + depth = linear Previous answer: 45 linear inches
45 divided by 5 = 9 9 x 3 = 27 27 + 45 = 72 (:
45 3/12 ft x 26 1/12 ft= 1 180 13/48 sqft