Suppose the angle is x degrees. Then its complement is 90 - x deg
So 90 - x = 4*x
ie 90 = 5x or x = 18 degrees.
25
explement of the angle or conjugate of an angle
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
Two complementary angles add up to 90 degrees. Hence, the problem can be set up and solved. Let x represent one angle and 5x represent the angle that is 5 times greater: x + 5x = 90 (simplify) 6x = 90 (next divide both sides by 6 to find the value of x [the smaller angle]) x = 15 (this is the smaller angle, next subtract 15 from 90 to find the greater angle) 90 - 15 = 75 (this is the greater angle which is 5 times that of its complement)
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
15°
go off
The angle= 36, the supplement= 144, the compliment=54
25
explement of the angle or conjugate of an angle
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
Suppose the angle is x then its complement is 90-x So 4*(90-x) = x or 360 - 4x = x so that 360 = 5x => x = 72 degrees
Two complementary angles add up to 90 degrees. Hence, the problem can be set up and solved. Let x represent one angle and 5x represent the angle that is 5 times greater: x + 5x = 90 (simplify) 6x = 90 (next divide both sides by 6 to find the value of x [the smaller angle]) x = 15 (this is the smaller angle, next subtract 15 from 90 to find the greater angle) 90 - 15 = 75 (this is the greater angle which is 5 times that of its complement)
Complementary angles add up to 90 degrees. If one angle is five times the measure of the other, you can express their measurements as 5x and x. The original angle is x degrees and its complement is 5x degrees. Set the sum of the two angles equal to 90 and solve for x. 5x + x = 90 6x = 90 x = 15 The angle is 15 degrees. Its complement is 5(15) = 75 degrees. 75 + 15 = 90.
Suppose the angle is x degrees. Then its complement is x/5 deg So x + x/5 = 90 or 6x = 450 ie x = 75 degrees.
an angle that is 54 degrees less than 4 times its complement
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°