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The first step in the construction of a perpendicular bisector is to draw a what?
Watermelon8
Equilateral triangle
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Why?
Draw an arc, greater than half the distance of the line segment, from one of the end points. Another arc, using the same radius from the other end. Jion the two points where the arcs intersect - one on each side of the line. At best you get two isosceles triangles if yu join up other lines (which is not required), but certainly no equilaterals!
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because it's APEX and it's stupid in ways you can't understand
Wiki User
∙ 11y ago
D’lbert Galindo
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A first step in the construction of a perpendicular bisector is to draw a n?
Open the compass to a little more than half the distance between the two points. Draw arcs from above the line to below the line from each end. This will look a little bit like an American football. The line that goes through the pointed ends of the football is the perpendicular bisector.
What is a method for constructing a regular quadrilateral?
Start with constructing a circle, then make a diameter from that circle. After you've done that, construct the perpendicular bisector of, the diameter, then draw the line in from the perpendicular bisector. After you've done that, connect the 4 points you have on the circle... then you're done. ^^ Hope this helps. :)
Construct a circle with a radius r. mark a point on the circle. construct a tangent thourgh this point.?
1) draw the circle with a radius r and the center at O. 2) mark a point, A, on the circle 3) draw a line from O to A and beyond to point B, a little longer than the radius 4) draw a perpendicular bisector at point A using line OB 5) the perpendicular bisector is the tangent at point A In case, you forgot about drawing the perpendicular bisector. Here is the procedure: a) use your compass and mark equidistant points C and D from point A on line OB (make the length slightly less than half the radius); one point should be outside the circle and the other within. b) use your compass and draw an arc from point C and then from point D, with the arc radii being identical and about as long as the circle radius; the two arcs should intercept at two locations, E and F, one on each side of line OA. c) join points E and F to form the perpendicular bisector of line CD ===============================
How is diameter measured?
Let us assume you have a circle drawn with the center identified. Then draw one straight line through the center. Measure the length of the line bound by the intercepts of the straight line with the circumference of the circle. The line segment is the diameter. Another case would be that you have a circle drawn with no center marked. Draw one straight line through the circle. Use a compass to draw the perpendicular bisector of the line segment bound by the intercepts of the straight line with the circumference of the circle toward the inner circle (the center of a circle cannot lie outside the circle!). Repeat drawing another (different) straight line through the circle and finish with a perpendicular bisector. The two bisectors will intercept at the center of the circle. Then you can proceed the same way as described in the first paragraph above. Hint to draw a perpendicular bisector of a line segment: take one end of the compass, pivot the point at one end of the line segment and mark an arc with the other end on both sides of the line. Move the compass and pivot one point at the other end of the line segment. Mark an arc with the other end on both sides of the line. If the procedure is done correctly, the two arcs, one from each end, should intercept on one side of the line. There is another intercept of the two arcs on the side of the line. Connect the two arc-intercepts with a straight line. Convince yourself that the line bisects the straight line at a right angle. This last line is the perpendicular bisector of the original line (The first and last lines form the perpendicular bisector of one another). ===================
How would you draw a perpendicular line?
Using a compass and ruler: # At the point you want the perpendicular line to cross, place a dot. Label it A. # Draw a circle centred at A with a radius of about an inch (two-three centimetres). Label the points it intersects the original line as B and C. # Construct two circles centred at B and C, large enough that they almost reach the other point and have the same size. Label the points they intersect at as D and E. # Draw a straight line between E and D. This line is the perpendicular line. This method can also be used to draw a perpendicular bisector, if the ends of the line you wish to bisect are labelled as points B and C.
The first step in the construction of a perpendicular bisector is to draw a?
equilateral triangle ;)
How do you draw a perpendicular bisector of an angle?
The right way
A first step in the construction of a perpendicular bisector is to draw a n?
Open the compass to a little more than half the distance between the two points. Draw arcs from above the line to below the line from each end. This will look a little bit like an American football. The line that goes through the pointed ends of the football is the perpendicular bisector.
How do you draw parallel perpendicular bisector?
Two lines cannot be parallel and perpendicular at the same time.
You can draw a perpendicular bisector to a segment using paper-folding constructions?
true.
What do you need to do to prove a line is an angle bisector of an angle?
Draw a perpendicular to that line and extend the arms of the angle to meed the perpendicular drawn earlier. Check if the line is bisecting the perpendicular, if yes, then the line is a bisector of the angle. :)
You can draw a perpendicular bisector to a using paper-folding constructions?
haterz gonna hate but it is yes
joaquin is constructing the perpendicular bisector of ab. what should be his first step?
Place the point if the compass on point B and draw an arc across AB.
How can you construct an isosceles triangle if only given the base and the vertical angle and the base angles can not be used for construction?
The answer depends on the level of your knowledge. Suppose the base is of length b and the vertical angle is x degrees. Draw the base, AC, and its perpendicular bisector. Calculate h = b/[2*tan(x/2)]. That is the height of the triangle so mark this point, B, on the perpendicular bisector. Draw AB and BC. Done!
How do you find radius of a circle?
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
Joaquin is constructing the perpendicular bisector of line AB. What should be his first step?
Place the point if the compass on point B and draw an arc across AB.
What is a method for constructing a regular quadrilateral?
Start with constructing a circle, then make a diameter from that circle. After you've done that, construct the perpendicular bisector of, the diameter, then draw the line in from the perpendicular bisector. After you've done that, connect the 4 points you have on the circle... then you're done. ^^ Hope this helps. :)
