Let's denote the width of the rectangle as W. Since the length L is 3 times the width, we have L = 3W. The perimeter of a rectangle is given by P = 2(L + W). Given that the perimeter is greater than 48 cm, we have 2(3W + W) > 48. Simplifying this inequality gives 8W > 48, which further simplifies to W > 6. Therefore, the inequality expressing all possible lengths in centimeters of the rectangle is L > 18.
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
The width of the rectangle is 4 cm
2+2+15+15=34cm
6cm. The perimeter of the rectangle has to add to 20. 4+4+6+6=20 Hope this helps ;-)
what is the perimeter of the rectangle
What is the perimeter of a rectangle 5 meter by 650 centimeters?
the answer is 16 cm and that is the perimeter.
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
The answer is 12 cm.
Perimeter of rectangle = (length * 2) + (height * 2 Perimeter = (50.7 * 2) + (40.8 * 2) Perimeter = 183cm
22
If the shape measuring 8 centimeters by 5 centimeters is a rectangle, the perimeter of the rectangle is 25 centimeters (2w + 2l)
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
30 ft
21cm3
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
58 cm