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The length L of a rectangle is 3 times its width The perimeter of the rectangle is greater than 48 centimeters Which inequality expresses all the possible lengths in centimeters of the rectangle?
Wiki User
∙ 7y ago
Number of miles in the car can travel varies directly with the amount of gas in its fuel tank if K is the concert which equation represents that situation
Wiki User
∙ 7y ago
Wiki User
∙ 10y agoL = 3W so W = L/3
2*(L + L/3) > 48 cm
L + L/3 > 24 cm
4L/3 > 24 cm
L > (3/4)*24 cm
L > 18 cm.
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If the shape measuring 8 centimeters by 5 centimeters is a rectangle, the perimeter of the rectangle is 25 centimeters (2w + 2l)
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the width of a rectangle is w centimeters. the length of this rectangle is three times its width. the perimeter of the rectangle is greater than 64 centimeters. give the inequality that represents all possible values of w?
Let's set up an inequality to represent all possible values of the width (w) of the rectangle given the information provided. The length of the rectangle is three times its width, so the length (L) can be expressed as L = 3w. The perimeter (P) of a rectangle is given by the formula: P = 2(L + w). The perimeter is greater than 64 centimeters, so we have P > 64. Now, substitute the expression for L from step 1 into the perimeter formula from step 2: P = 2(3w + w) Simplify the expression inside the parentheses: P = 2(4w) P = 8w Now, we have the perimeter in terms of the width: P = 8w. We already know that P > 64, so we can write the inequality: 8w > 64 To isolate w, divide both sides of the inequality by 8: w > 64 / 8 w > 8 So, the inequality representing all possible values of the width (w) is: w > 8 This means that the width of the rectangle must be greater than 8 centimeters for the perimeter to be greater than 64 centimeters.
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The length of a rectangle is 4 centimeters longer than the width If the perimeter of the rectangle is 20 centimeters what is the area of the rectangle?
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