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The length of a rectangle is 8 inches greater than its width find the width of the rectangle if its area is 105 sq inches?
Let the length be (x+8) and the width be x:
length*width = area
(x+8)*x = 105 sq inches
x2+8x = 105
x2+8x-105 = 0
Solving the above quadratic equation works out as :
x = -15 or x = 7 it must be the latter because dimensions can't be negative.
Therefore: width = 7 inches and length = 15 inches
Check: 7*15 = 105 sq inches
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The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
What is the area of a rectangle with a length of 12 inches and a width of 7 inches?
Area = Length * Width = 12*7 = 84 square inches.
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A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
What is the area of a rectangle with length of 6 inches and width of 2 feet?
Conventionally length (6 inches) is greater than width (24 inches), but leaving that aside, the area of the rectangle is 6 in * 24 in = 144 sq inches. Alternatively, it is 0.5 ft * 2 ft = 0.5 * 2 = 1 sq ft.
If the area of a rectangle is 40 square inches and the length is 6 inches more than the width what is the length and the width of the rectangle?
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
The length of a rectangle is 8 inches greater than its width Find the width of the rectangle if its area is 105 square inches?
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What is the width of a rectangle with the length of 8 inches greater than its width find the width of the rectangle if its area is 105 square inches?
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches
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Any length greater than six.
The length of a rectangle is 2 inches greater than the width the area is 80 inches squared find the length of the rectangle?
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What is the width of a rectangle with the length of 8 inches greater than its width the area is 105?
15 x 7 = 105...
The length of a rectangle is 8 inches greater than its width Find the width of the rectangle if its area is 105 square inch?
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