Let the length be (x+8) and the width be x:
length*width = area
(x+8)*x = 105 sq inches
x2+8x = 105
x2+8x-105 = 0
Solving the above quadratic equation works out as :
x = -15 or x = 7 it must be the latter because dimensions can't be negative.
Therefore: width = 7 inches and length = 15 inches
Check: 7*15 = 105 sq inches
Area = Length * Width = 12*7 = 84 square inches.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
Conventionally length (6 inches) is greater than width (24 inches), but leaving that aside, the area of the rectangle is 6 in * 24 in = 144 sq inches. Alternatively, it is 0.5 ft * 2 ft = 0.5 * 2 = 1 sq ft.
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
The area of rectangle is : 30.0
7
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches
Any length greater than six.
10 in. A+LS
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
if the length is 36 on a rectangle then what is the width of the rectangle
Length 7 inches and width 4 inches because 7*4 = 28 square inches
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
if a rectangle is 450 square inches and the length is 24 inches what is the width?
15 x 7 = 105...
105 = 7 x 15.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.