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Let the length be (x+8) and the width be x:

length*width = area

(x+8)*x = 105 sq inches

x2+8x = 105

x2+8x-105 = 0

Solving the above quadratic equation works out as :

x = -15 or x = 7 it must be the latter because dimensions can't be negative.

Therefore: width = 7 inches and length = 15 inches

Check: 7*15 = 105 sq inches

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Q: The length of a rectangle is 8 inches greater than its width find the width of the rectangle if its area is 105 sq inches?
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