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Answer: 30 yards. Explanation: let's say it is L yards long and W yards wide. Then perimeter is 2L+2W The area is LxW=50 So Since LW=50, we substitute L=2W and write 2W(W)=2W^2=50. so W^2=50/2=25 and W=5 Now 2W=10 which is L So is it 10 yards long and 5 yards wide Let's check that. Area is 10x5=50 as desired and Length is 10 which is twice 5 as desired Now perimeter is 2L+2W=2(10)+2(5)=20+10=30 yards.

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Q: The length of a rectangle is twice its width If the area of the rectangle is 50yds2 What is the perimeter?
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What is the perimeter in feet of a rectangle whose length is twice its width and whose width is 9 feet?

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