L=360
W=160
2L+2W=Perimeter
2(3W-120)+2(W)=1040
6W-240+2W=1040
8W-240=1040
8W=1280
W=160
L=3W-120
L=(3*160)-120
L=480-120
L=360
Field = 5y x1y where y depicts the measurement and 5:1 is the ratio. The perimeter of the field = 325 yards, assuming that opposite sides of the field are of equal length. Therefore assume that the perimeter of the field = 1y+1y+5y+5y =12y Set 12y = 325 yards to get y=27.0833 yards Therefor the field is 135.4167 yards x 27.0833 yards.
Minimum width: 18.30m (20 yards)Maximum width: 27.45m (30 yards)Minimum length: 27.45m (30 yards)Maximum length: 45.75m (50
L + W = 87. L = 2W + 9 so (2W + 9) + W = 87 ie 3W = 78 so Width is 26 m and Length is 61 m.
Well, isn't that a fun question! A football field is a rectangular shape, so it doesn't have a square root like a square would. But if we imagine the area of a football field as a square, we could find the square root by taking the square root of the area in square units. Just remember, math can be as creative and imaginative as painting a happy little tree!
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The perimeter is 328 m. (Width: 64m length: 100m)
Since the dimensions of a standard football field are 105 x 68m, and a football field is a rectangle, then 105 + 68 + 105 + 68 = 346, so the perimeter is 346m.
The length is 10 meters and the width is 5 meters
cc
346m
120
5,347,962,110 Miles
If the perimeter is 346 and the length is 67 yards longer then the width.Then346 = 2x + 2(x+67) = 4x + 1344x = 212x = 53The width is 53 yards53 + 67 = 120The length is 120 yardsTo check 120 + 53 + 120 + 53 = 346
No. Same dimensions
The answer may vary. If you take a square away from the field it will still have the same perimeter. So the Length and Width may vary on how you make the field.
A professional sized pitch is 300m in perimeter two 100m sides by two 50m ends
1.o-1.5%