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The perimeter of a rectangle is 18 feet and the area is 14 square feet what is the length and width?
Wiki User
∙ 13y ago
*This is easily guessed but the albegraic solution uses two equations, perimeter and area.
Perimeter = twice the length plus twice the width = 2L + 2W
Area = length times width = L * W
P = 2L + 2W = 18
A = L * W = 14
2L = (18 - 2W) and L = (18 - 2W) / 2 so L = 9 - W
Substituting this value in the Area equation
A = L*W = (9 - W) * W = 14
The equation W2 - 9 W +14 = 0 has the solutions (W - 7)(W - 2) = 0
The dimensions must be 7 feet by 2 feet (either can be length or width).
Wiki User
∙ 13y ago
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