*This is easily guessed but the albegraic solution uses two equations, perimeter and area.
Perimeter = twice the length plus twice the width = 2L + 2W
Area = length times width = L * W
P = 2L + 2W = 18
A = L * W = 14
2L = (18 - 2W) and L = (18 - 2W) / 2 so L = 9 - W
Substituting this value in the Area equation
A = L*W = (9 - W) * W = 14
The equation W2 - 9 W +14 = 0 has the solutions (W - 7)(W - 2) = 0
The dimensions must be 7 feet by 2 feet (either can be length or width).
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
Perimeter is 36 mArea is 72 square m
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
To find the area of a rectangle, you need to know the formula: Area = length x width. Given that the perimeter is 72m and the width is 16m, we can calculate the length by using the formula for perimeter of a rectangle: Perimeter = 2(length + width). Substituting the values we have, 72 = 2(length + 16), which simplifies to length + 16 = 36. Therefore, the length of the rectangle is 20m. Finally, the area of the rectangle is 20m x 16m = 320 square meters.
width=9 length=18
The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
Length: 4; Width: 5 or Length: 5; Width: 4
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
Perimeter is 36 mArea is 72 square m
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Perimeter of a rectangle = 2 x (length + width) = 2 x (2 + 9) = 2 x 11 = 22 square inches.