Best Answer

*This is easily guessed but the albegraic solution uses two equations, perimeter and area.

Perimeter = twice the length plus twice the width = 2L + 2W

Area = length times width = L * W

P = 2L + 2W = 18

A = L * W = 14

2L = (18 - 2W) and L = (18 - 2W) / 2 so L = 9 - W

Substituting this value in the Area equation

A = L*W = (9 - W) * W = 14

The equation W2 - 9 W +14 = 0 has the solutions (W - 7)(W - 2) = 0

The dimensions must be 7 feet by 2 feet (either can be length or width).

Q: The perimeter of a rectangle is 18 feet and the area is 14 square feet what is the length and width?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.

Perimeter is 36 mArea is 72 square m

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters

width=9 length=18

Related questions

The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).

perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)

Length: 4; Width: 5 or Length: 5; Width: 4

Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.

Perimeter is 36 mArea is 72 square m

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.

The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm

If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

The length of the rectangle is 18cm. The width of the rectangle is 9cm.

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.