The number in the units digit of the number 921 is 9.
To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is (9). Thus, the units digit of (29^{57}) is (9).
The units digit of 159*445*7762*39 is the units digit of the product of the units digits of the four numbers, that is, the units digit of 9*5*2*9 Since there is a 5 and a 2 in that, the units digit is 0.
To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
The units digit of 9n is 9 if n is odd and 1 if n is even. So 1.
The 9 in 879 represents nine ones or nine units
To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is (9). Thus, the units digit of (29^{57}) is (9).
The units digit of 159*445*7762*39 is the units digit of the product of the units digits of the four numbers, that is, the units digit of 9*5*2*9 Since there is a 5 and a 2 in that, the units digit is 0.
9
It is the unit's digit of the product of the unit's digits. For example, the units digit of 123456 * 4689 is simply the units digit of 6*9 = 54, which is 4.
Power 2: units digit 9. Multiply by 49 again to get power 4: units digit 1. So every 4th power gives units digit 1. So 16th power has units digit 1, so the previous power, the 15th must have units digit 3.
99. 9 divided by 9=1
899 means 8 x 100s + 9 x 10s and 9 x units. So the 9 on the right hand side is the units.
To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
'5' is the UNIT digit. '6' is the 'tenths' digit. '9' is the 'hundredths' digit.
The units digit of 9n is 9 if n is odd and 1 if n is even. So 1.
The 9 in 879 represents nine ones or nine units
The "7" digit had the greatest value because it is in the UNITS column.