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The second of two numbers is 4 times the first their sum is 45?
Wiki User
∙ 15y ago
This problem asks us to find 2 numbers, n1 and n2, with the following relations between them:
* n2 = 4 n1 * n1 + n2 = 45 Substituting the first equation into the second one gives us:
* n1 + 4n1 = 45 which gives us
* n1 = 9. We can now use this solution to find n2 with the first equation
* n2 = 4 n1 = 36 So the first number is 4, the second number is 36.
Wiki User
∙ 15y ago
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