Odd numbers
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{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
The answer is 3 over 7. First you have to set up the equation like how you just did. Then you multiply numerator to numerator and denom. to denom. and you get 12 over 28 which reduces to 3 over 7 when you divide the numerator and denomerator by 4.
The domain of 1 3 5 5 7 7 can not be given because it is not a function.
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
9+7+5+3+1 16+5+3+1 21+3+1 24+1 25