Odd numbers
The answer is 3 over 7. First you have to set up the equation like how you just did. Then you multiply numerator to numerator and denom. to denom. and you get 12 over 28 which reduces to 3 over 7 when you divide the numerator and denomerator by 4.
{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
The domain of 1 3 5 5 7 7 can not be given because it is not a function.
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
9+7+5+3+1 16+5+3+1 21+3+1 24+1 25
{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}
3
The subsets of the set {1, 2, 3, 4, 5, 6, 7} include all possible combinations of its elements, including the empty set and the set itself. In total, there are (2^n) subsets, where (n) is the number of elements in the set. For the set {1, 2, 3, 4, 5, 6, 7}, which has 7 elements, there are (2^7 = 128) subsets. These subsets range from the empty set {} to the full set {1, 2, 3, 4, 5, 6, 7}.
The mean of a set of data is the sum of all those data values, divided by the numbers of values in the set. For instance, if we had 1, 3 and 5, the mean would be (1+3+5)/3 = 3. The mean doesn't always have to be one of the data points in the set. For instance, if we had the data 1, 6, 7, 7, 8. The mean would be (1+6+7+7+8)/5 = 5.8, even though 5.8 isn't one of the values in the set.
The set of numbers is bimodal with modes 3 and 5.
Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3
(1, 2, 3, 4, 5, 6, 7)
The set of natural numbers less than 7 consists of the numbers 1, 2, 3, 4, 5, and 6. This set can be denoted as {1, 2, 3, 4, 5, 6}. Natural numbers are positive integers starting from 1, and in this case, we only include those below 7. Thus, the complete description of the set is {1, 2, 3, 4, 5, 6}.
The median is 4.5
The subsets of the set {1, 2, 3, 4, 5, 6, 7} include all possible combinations of its elements, including the empty set and the set itself. There are a total of (2^7 = 128) subsets. Some examples are the empty set {}, {1}, {2}, {1, 2}, {3, 4, 5}, and {1, 2, 3, 4, 5, 6, 7}. Each subset can be formed by including or excluding each of the seven elements.
The number 1315171921 can be expressed in set builder notation as the set of all individual digits: {1, 2, 3, 5, 7, 9}. Using roster method, this can be written as: {1, 1, 1, 2, 1, 5, 1, 7, 1, 9}. However, to avoid repetition in set notation, we simplify it to {1, 2, 5, 7, 9}.
0.6