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Odd numbers

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What is The set of all odd natural numbers less than 9 is?

{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}


What is the mode of this set of data 1 5 9 7 3 3 4?

3


What are the subsets of 1234567?

The subsets of the set {1, 2, 3, 4, 5, 6, 7} include all possible combinations of its elements, including the empty set and the set itself. In total, there are (2^n) subsets, where (n) is the number of elements in the set. For the set {1, 2, 3, 4, 5, 6, 7}, which has 7 elements, there are (2^7 = 128) subsets. These subsets range from the empty set {} to the full set {1, 2, 3, 4, 5, 6, 7}.


How mean of a data set is always one of the data points in a set of data. Explain?

The mean of a set of data is the sum of all those data values, divided by the numbers of values in the set. For instance, if we had 1, 3 and 5, the mean would be (1+3+5)/3 = 3. The mean doesn't always have to be one of the data points in the set. For instance, if we had the data 1, 6, 7, 7, 8. The mean would be (1+6+7+7+8)/5 = 5.8, even though 5.8 isn't one of the values in the set.


What is the mode out of these numbers 1 3 3 5 5 6 7 8 14?

The set of numbers is bimodal with modes 3 and 5.


What five odd numbers add up to twenty-one?

Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3


What is the set of counting numbers less than 8?

(1, 2, 3, 4, 5, 6, 7)


What is the median of this set 4 5 3 2 7 5 4 8 5 1?

The median is 4.5


What is 5 sevenths divided by 3?

0.6


What is the answer of 1315171921 using roster method set builder notation?

The number 1315171921 can be expressed in set builder notation as the set of all individual digits: {1, 2, 3, 5, 7, 9}. Using roster method, this can be written as: {1, 1, 1, 2, 1, 5, 1, 7, 1, 9}. However, to avoid repetition in set notation, we simplify it to {1, 2, 5, 7, 9}.


How does 1 3 5 7 9 equal 3?

{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3


What is 4 x 3 over 7?

The answer is 3 over 7. First you have to set up the equation like how you just did. Then you multiply numerator to numerator and denom. to denom. and you get 12 over 28 which reduces to 3 over 7 when you divide the numerator and denomerator by 4.