11, 9, 7, 5, 3, 1, -1, -3, -5, -7, ... and so on - forever.
The answer is 3 over 7. First you have to set up the equation like how you just did. Then you multiply numerator to numerator and denom. to denom. and you get 12 over 28 which reduces to 3 over 7 when you divide the numerator and denomerator by 4.
{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
The domain of 1 3 5 5 7 7 can not be given because it is not a function.
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}
3
11, 9, 7, 5, 3, 1, -1, -3, -5, -7, ... and so on - forever.
The mean of a set of data is the sum of all those data values, divided by the numbers of values in the set. For instance, if we had 1, 3 and 5, the mean would be (1+3+5)/3 = 3. The mean doesn't always have to be one of the data points in the set. For instance, if we had the data 1, 6, 7, 7, 8. The mean would be (1+6+7+7+8)/5 = 5.8, even though 5.8 isn't one of the values in the set.
The set of numbers is bimodal with modes 3 and 5.
Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3
(1, 2, 3, 4, 5, 6, 7)
The median is 4.5
0.6
The answer is 3 over 7. First you have to set up the equation like how you just did. Then you multiply numerator to numerator and denom. to denom. and you get 12 over 28 which reduces to 3 over 7 when you divide the numerator and denomerator by 4.
{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1