The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
If the digit sum of a number is 9 then it is divisible by 9
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.
81 8+1=9 9*9=81
The sum of fluorine is 9, as it has an atomic number of 9.
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
The sum of 32 is 9.
The rule to decide if a number is divisible by 9 is to look at the sum of the digits. If the sum of the digits is divisible by 9, then so is the number.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
let the no. be 9 square of 9=9*9=81 sum of the digits of square = 8+1=9 so if the no.=sum of the digits the it is a neon number
If the digit sum of a number is 9 then it is divisible by 9
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
The sum of a number plus 3 to the square root of 9 to the sum of 2 would equal -2. This is a math problem.
subtract any number form nine and then with that answer and the number you subtracted 9 with, those added, make the sum of nine
x + 9 = n
Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.