Let the 2 digit number be 10a +b. Then:
a + b = 15
10a + b - 27 = 10b + a
=> 9a -9b = 27
=> a - b = 3
adding the first and last equations gives:
2a = 18
=> a = 9
and substituting in the first gives:
9 + b = 15
=> b = 6
meaning the original number is 96.
Find a four digit number whose digits will be reversed when multiplied by nine?
192
The number you are looking for is 12. Reversing the digits gives you 21 75% of 12 is 9 12 + 9 = 21
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
Possibility of two digit no whose sum is 17 89 and 98 Reverse of 89 is 98. 98 is 9 less than the original no 89. 89 is original no
Find a four digit number whose digits will be reversed when multiplied by nine?
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
45
17
100000 2847239582
2178
The number is 36
47 Impossible problem!
86420
2178 * 4 = 8712
192