Consecutive numbers follow this series: n, n + 1, n + 2, n + 3..... etc.
963 = (n) + (n + 1) + ( n + 2)
963 = n + n + n + 3
963 = 3n + 3
- 3 - 3
960 = 3n
/ 3 /3
n = 320
and since the numbers follow the sequence (n), (n + 1), (n + 2) the numbers are 320, 321, and 322.
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
No. Every third consecutive natural number is divisible by 3.
The answer to that question is 49,50,51
This is no set of three consecutive numbers that when multiplied equal 387.
71,72,73 :)
No.
0, 1, 2
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
5 + 6 + 7 = 18 Consecutive numbers means numbers following one another in sequence.
2, 3Those two are consecutive, natural and prime numbers! It's as easy as one, two, three! (Pun intended)
No. Every third consecutive natural number is divisible by 3.
It is a statement of numerical fact.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
There are no three consecutive numbers with a sum of 170.
The answer to that question is 49,50,51
There are no sets of three consecutive numbers totaling 118.
19, 20, 21