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There are more than one answer for you question. Here are the answers: * 0+45 * 1+44 * 2+43 * 3+42 * 4+41 * 5+40 * 6+39 * 7+38 * 8+37 * 9+36 * 10+35 * 11+34 * 12+33 * 13+32 * 14+31 * 15+30 * 16+29 * 17+28 * 18+27 * 19+26 * 20+25 * 21+24 * 22+23 So there are twenty-three answers not counting integers. Integers are positive numbers and their opposites. (In other words, integers are positive and negative numbers.) Answered by: QWERTY

Q: The sum of two numbers is 45. The first is less than the second. Find the numbers?

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45

57

a=58.4615 b=5.2308 c=41.3076

This question has no answer, probably because of a typo. If you change 52 to 32, there will be exactly one solution.

143, 157

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45

57

a=58.4615 b=5.2308 c=41.3076

The second set of numbers are less variable; the coefficient of variation is halved. The second set of numbers are less variable; the coefficient of variation is halved. The second set of numbers are less variable; the coefficient of variation is halved. The second set of numbers are less variable; the coefficient of variation is halved.

Let x represent the first number; 2x - 3 then represents the second number. x + 2x - 3 = 75 3x = 78 x = 26 2x - 3 = 49 So the numbers are 26 and 49.

This question has no answer, probably because of a typo. If you change 52 to 32, there will be exactly one solution.

143, 157

There are several options. The first is 200 less than the second. The first is half of the second. The first is the square root of the second when the latter is expressed as a percentage. and others.

One option for comparing two numbers is to subtract the first number from the second number. If the result is less than zero, the first number is larger. If the result is greater than zero, the second number is larger. If the result is zero, the numbers are equal. Another option (for positive numbers) would be to divide the first number by the second number. If the result is greater than one, the first number is larger. If the result is less than one, the second number is larger. If the result is one, the numbers are equal. This rule flips if you are comparing negative numbers.

the sum of three numbers is 64. the second number is 3 less than the first number, the third number is 11 less than twice the first. what are the three numbers?

Assuming the two numbers are positive integers, the two numbers must be 10 and 7: 10 + 7 = 17 10 - 7 = 3

Call x the first number: Then the second number must be 2x - 3 So x + (2x - 3) = 36 Now solve to get 3x - 3 = 36 3x = 39 x = 13 So the two numbers are 13 and (13 x 2) - 3 = 23