Vertex = (3, - 2)
Put in vertex form.
(X - 3)2 + 2
X2 - 6X + 9 + 2 = 0
X2 - 6X + 11 = 0
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The coefficeint of the squared term is 1. My TI-84 confirms the (4, 3) intercept of the parabola and the 11 Y intercept shown by the function.
-3
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
Go study
Assuming that a is the leading coefficient of the equation of the parabola, changing it from positive to negative will reflect the parabola along a horizontal line through its minimum - which will then become its maximum.
Not really, parabolas aren't 3D like cones.
A coefficient is a number that accompanies a variable. For example, in the expression 2x + 4, the coefficient is 2.
The vertex of this parabola is at -3 -1 When the y-value is 0 the x-value is 4. The coefficient of the squared term in the parabolas equation is 7
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.
It is 1/16.
7
-3
-3
u look at it.... :-) hey I'm learning about parabolas too
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
Go study
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2. The coefficient of the squared expression in the parabola's equation is 4. y = a(x - h)2 + k; (h, k) = (-5, -2); (x, y) = (-4, 2) 2 = a[-4 -(-5)]2 - 2, add 2 to both sides 4 = a(-4 +5)2 4 = a(1)2 4 = a
right