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In a cube, V = s^3, so V1 = 2^3 = 8 and V2 = 4^3 = 64. V1/V2 = 8/64 = 1/8, so the smaller cube is one eight the volume despite being only half the height of the larger cube.

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Q: These cubes have sides of 2 cm and 4 cm respectively What is the ratio of their volumes?
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