To find sum of odd position digits and even position digits separately?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int oddSum = 0, evenSum = 0, i = 0;

char n[50] = {0};

clrscr();

printf("Enter the number : ");

scanf("%s", n);

while(n[i] != '\0')

{

if(i % 2 == 0)

oddSum = oddSum + (n[i] - 48);

else

evenSum = evenSum + (n[i] - 48);

++i;

}

printf("Odd sum is %d and even sum is %d\n", oddSum, evenSum);

getch();

}