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How do you get the binomial cube of 3m-2n 3?
To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula: (a+b)3 = a3 + 3a2b + 3ab2 + b3 ... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
How do you get the cube of a binomial?
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
When is the product of two binomials also a binomial?
(a-b) (a+b) = a2+b2
How do you find the coefficients of the terms in the binomial expansion?
The coefficient of x^r in the binomial expansion of (ax + b)^n isnCr * a^r * b^(n-r)where nCr = n!/[r!*(n-r)!]
Is 3X cubed minus 2X squared a binomial?
No, it isn't. You can express 3x3-2x2 as 3x3-2x2+0x+0, so it actually has four terms. The definition of a binomial is an expression in the form Ax+b, where A and b are constants, so 3x3-2x2 is not a binomial. It is actually a quartomial.
How do you factor perfect square binomial?
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
How can the context-free grammar CFG be defined in terms of the variables i, j, and k, where i is equal to j plus k, and the grammar generates strings consisting of a raised to the power of i, b raised to the power of j, and c raised to the power of k?
In the context-free grammar CFG, the variables i, j, and k represent the exponents of a, b, and c respectively in the generated strings. The variable i is equal to the sum of j and k. The grammar produces strings with a raised to the power of i, b raised to the power of j, and c raised to the power of k.
How do you get the binomial cube of 3m-2n 3?
To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula: (a+b)3 = a3 + 3a2b + 3ab2 + b3 ... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
How do you get the cube of a binomial?
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
X2 -5kx plus 25 the square of binomial. what is a possible value of k?
k can be 2 or -2. A binomial squared is: (a + b)² = a² + 2ab + b² Given x² - 5kx + 25 = (a + b)² = a² + 2ab + b² we find: a² = x² → a = ±x 2ab = -5kx b² = 25 → b = ±5 If we let a = x, then: 2ab = 2xb = -5kx → 2 × ±5 = -5k → k = ±2 If k = 2 then the binomial is (x - 5)² If k = -2 then the binomial is (x + 5)² To be complete if a = -x, then: If k = 2 then the binomial is (-x + 5)² If k = -2 then the binomial is (-x - 5)² which are the negatives of the binomials being squared.
How do you solve a to the 3rd power plus b to the 3rd power divided by a plus b?
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
How do you write 25 as a power?
You write it in superscore, such as b25 or B raised to the 25th power
A raised to power b in C programming?
#include <math.h> double a, b, result; result = pow (a, b);
What are the steps to solve these problems Find the degree of each polynomial 5a-2b2 plus 1 and 24xy-xy3 plus x2?
The degree of a polynomial function is the highest power any single term is raised to. For example, (5a - 2b^2) is a second degree function because the "b^2" is raised to the second power and the "a" is only raised to the (implied) first power. For (24xy-xy^3 + x^2) it is a third degree polynomial because the highest power is the cube of -xy.
How do you factor the perfect square binomial?
(a^2 - b^2) = (a - b)(a + b)
WHAT IS a to the power 3 plus b to the power 3?
a3+b3
What is the greatest common factor of a power plus b power and a plus b cubed?
The question cannot be answered because the powers of a and b, at the start of the expression are not specified.
