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What is the equation of a circle having a diameter with endpoints -3 1 and 5 7?
The equation works out as: (x-1)2+(y-4)2 = 25 whereas (1, 4) is the circle's centre and 25 is the radius2
What is the equation of a circle whose endpoints of its diameter are at 2 2 and 10 -4 on the Cartesian plane showing work?
Endpoints: (2, 2) and (10, -4) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (2, 2) or (10, -4) = 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the equation of Pi?
there is no equation of Pi Circumference divided by diameter
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
What is the equation for the diamiter of a circle?
Diameter = 1/2 of the circle's radius. Diameter = 2 times the square root of (the circle's area/pi) Diameter = the circle's circumference/pi
What is the equation of a circle having a diameter with endpoints -3 1 and 5 7?
The equation works out as: (x-1)2+(y-4)2 = 25 whereas (1, 4) is the circle's centre and 25 is the radius2
What is an equation of the circle whose diameter has endpoints -3 1 and 5 -2?
The equation works out as: (x-1)2+(y+0.5)2 = 18.25 Equation of a circle: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circle's centre
What is the equation of a circle when the endpoints of its diameter are at 10 -4 and 2 2 on the Cartesian plane?
Endpoints: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (10, -4) or (2, 2): 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
Which equation will determine the circumference of the circle with a diameter of 14cm and a radius of 7cm?
C=2 pi R
What is the equation of a circle whose endpoints of its diameter are at 2 2 and 10 -4 on the Cartesian plane showing work?
Endpoints: (2, 2) and (10, -4) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (2, 2) or (10, -4) = 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the equation of a circle whose diameter endpoints are at 2 -3 and 8 7 on the Cartesian plane and what are the tangent equations touching its endpoints showing work?
Endpoints: (2, -3) and (8, 7)Centre of circle: (5, 2)Radius of circle is the square root of 34Equation of the circle: (x-5)^2 +(y-2)^2 = 34Slope of radius: 5/3Slope of tangents: -3/51st tangent equation: y--3 = -3/5(-2) => 5y = -3x-92nd tangent equation: y-7 = -3/5(x-8) => 5y = -3x+59
How can you determine the circumference of a circle if you know it diameter?
The circumference of a circle (C) is the diameter (D) times pi (approximately 3.14 or 22/7). So, the equation would be: C=D*3.14. For example, if the diameter was 4', the circumference would be 12.56'.
What is the equation of Pi?
there is no equation of Pi Circumference divided by diameter
Which equation is the perpendicular bisector of the line segment with endpoints -2 4 and 6 8?
Endpoints: (-2, 4) and (6, 8) Slope: 1/2 Perpendicular slope: -2 Midpoint: (2, 6) Perpendicular bisector equation: y = -2x+10
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
If you Give a circle with a diameter of 4 what is the circumference?
the equation for the circumference of a circle is 2*radius*pi, or since the radius is half of the diameter 2*radius=diameter, we can simplify the equation to the circumference of a circle=diameter*pi
A line segment has endpoints of Y(2,-3) and Z(-6,-1).a. Calculate the length of the line segment.b. Calculate the midpoint of the line segment.c. Determine the equation of the line that passes through the points Y and Z?
who would know that answer
