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Two of the endpoints of the diameter of a circle are at A -6 and 8 and B 6 and -8 1. determine the radius of the circle 2. state an equation of the circle I appreciate the help.?
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∙ 13y ago
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∙ 13y ago
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What is the equation of a circle having a diameter with endpoints -3 1 and 5 7?
The equation works out as: (x-1)2+(y-4)2 = 25 whereas (1, 4) is the circle's centre and 25 is the radius2
What is the equation of a circle whose endpoints of its diameter are at 2 2 and 10 -4 on the Cartesian plane showing work?
Endpoints: (2, 2) and (10, -4) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (2, 2) or (10, -4) = 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the equation of Pi?
there is no equation of Pi Circumference divided by diameter
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
Explain how you an determine if the number is a solution of an equation?
Substitute the number in the equation. If the resulting statement is true the number is a solution to the equation.
What is the equation of a circle having a diameter with endpoints -3 1 and 5 7?
The equation works out as: (x-1)2+(y-4)2 = 25 whereas (1, 4) is the circle's centre and 25 is the radius2
What is an equation of the circle whose diameter has endpoints -3 1 and 5 -2?
The equation works out as: (x-1)2+(y+0.5)2 = 18.25 Equation of a circle: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circle's centre
Which equation will determine the circumference of the circle with a diameter of 14cm and a radius of 7cm?
C=2 pi R
What is the equation of a circle when the endpoints of its diameter are at 10 -4 and 2 2 on the Cartesian plane?
Endpoints: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (10, -4) or (2, 2): 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the equation of a circle whose endpoints of its diameter are at 2 2 and 10 -4 on the Cartesian plane showing work?
Endpoints: (2, 2) and (10, -4) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (2, 2) or (10, -4) = 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the equation of a circle whose diameter endpoints are at 2 -3 and 8 7 on the Cartesian plane and what are the tangent equations touching its endpoints showing work?
Endpoints: (2, -3) and (8, 7)Centre of circle: (5, 2)Radius of circle is the square root of 34Equation of the circle: (x-5)^2 +(y-2)^2 = 34Slope of radius: 5/3Slope of tangents: -3/51st tangent equation: y--3 = -3/5(-2) => 5y = -3x-92nd tangent equation: y-7 = -3/5(x-8) => 5y = -3x+59
How can you determine the circumference of a circle if you know it diameter?
The circumference of a circle (C) is the diameter (D) times pi (approximately 3.14 or 22/7). So, the equation would be: C=D*3.14. For example, if the diameter was 4', the circumference would be 12.56'.
Which equation is the perpendicular bisector of the line segment with endpoints -2 4 and 6 8?
Endpoints: (-2, 4) and (6, 8) Slope: 1/2 Perpendicular slope: -2 Midpoint: (2, 6) Perpendicular bisector equation: y = -2x+10
What is the equation of Pi?
there is no equation of Pi Circumference divided by diameter
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
A line segment has endpoints of Y(2,-3) and Z(-6,-1).a. Calculate the length of the line segment.b. Calculate the midpoint of the line segment.c. Determine the equation of the line that passes through the points Y and Z?
who would know that answer
How do you find the diameter of a circle if you have the circumference?
C=2(3.14)rThis is circumference equation for circles. If you have the circumference, you need to input it into the equation and solve for r. r is the radius of the circle, so to determine the diameter, which is 2 times the length of the radius, you just need to multiply the number you got for r times 2.
