Q: Use rhombus dklm with am as 4x ak as 5x-3 and dl as 10 find al?

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The answer depends on what information you do have about the rhombus. Assuming that you know the length of the sides and one of the diagonals, then,In the triangle formed by the given diagonal and the sides of the rhombus, you know all three sides. So you can use the cosine rule to calculate the angle between the sides of the rhombus.The other pair of angles in the rhombus are its supplement.So now you know two sides and the included angle of the triangle formed by the missing diagonal and the sides of the rhombus.You can use the cosine rule again to find the missing diagonal.

Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.

You need more information: the length of a side. Then, since the diagonals bisect one another at right angles, you can use Pythagoras's theorem to calculate their lengths.

To find the area, first divide the shape into regular, simple shapes. Then use formulas to find the area of the smaller, regular shapes. Lastly, add up all the smaller areas to find the area of the original shape.

Rhombus Area = side x height = 6 cm x 4 cm = 24 cm2In the right triangle formed by the side and the height of the rhombus, we have:sin (angle opposite to the height) = height/side = 4 cm/6cm = 2/3, so thatthe angle measure = sin-1 (2/3) ≈ 41.8⁰.In the triangle formed by two adjacent sides and the required diagonal, which is opposite to the angle of 41.8⁰ of the rhombus, we have: (use the Law of Cosines)diagonal length = √[62 + 62 -2(6)(6)cos 41.8⁰] ≈ 4.3Thus, the length of the other diagonal of the rhombus is about 4.3 cm long.

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To find the value of x in a rhombus, use these properties. All sides of a rhombus are the same length. Opposite angles of a rhombus are the same size and measure. Intersection of the diagonals of a rhombus form right angles. Sides are perpendicular. The diagonals of rhombus bisect each other. Adjacent angles add up to 180 degrees.

A rhombus is a square tilted on it's side. Or a rhombus is a diamond, or the sandbox looked like a rhombus.

I don't use the name "rhombus-quadrilateral", but perhaps the answer to your question is that a rhombus is a special kind of parallelogram

Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.

The answer depends on what information you do have about the rhombus. Assuming that you know the length of the sides and one of the diagonals, then,In the triangle formed by the given diagonal and the sides of the rhombus, you know all three sides. So you can use the cosine rule to calculate the angle between the sides of the rhombus.The other pair of angles in the rhombus are its supplement.So now you know two sides and the included angle of the triangle formed by the missing diagonal and the sides of the rhombus.You can use the cosine rule again to find the missing diagonal.

The diagonals of a rhombus (not rombhus) bisect one another at right angles. The sides of the rhombus form the hypotenuses of triangles whose other sides are half the diagonals. So use Pythagoras.

If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.

in math class we learn about rhombuses

Mental math is basically just giving an estimate of what the value will be, for example: 5x306= 5x3 and add 2 zeros will give you 1500 and the actual answer is 1530 so its kind of like rounding off to the nearest.

Yes, a square is a rhombus. It's just a specialized form or rhombus. Use the link to the Math Forum web site where this question is explained.No never. A square has four equal length sides and 90 degree angles in every corner. A rhombus has equal length sides, but they are not 90 degree angles

Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.

You need more information: the length of a side. Then, since the diagonals bisect one another at right angles, you can use Pythagoras's theorem to calculate their lengths.