Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.
Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.
Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.
Yes. There are lots of possible solutions. For example, a square of 4 x 4 has an area of 16. Adjust the angles (converting it into a rhombus), and you can lower the area all the way down to zero. Use trigonometry to find the correct angle.
Oh, what a happy little question! Let's think about shapes that could have a perimeter of 15 and an area of 16. One shape that comes to mind is a rectangle with dimensions 4 by 4. Another possibility is a square with sides of length 4. These shapes show us that there can be different ways to create beautiful combinations of perimeter and area.
4x4 square: perimeter - 16 area - 16 6x2 rectangle perimeter - 16 area - 12
The perimeter is all the way around the shape so it would be.. 16 + 16 + 2 + 2 = 36. Therefore th perimeter must be 36cm.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.
The perimeter is 16 feet.
It depends on the shape. Any area up to 20.37 square cm is possible.
Yes a 2 by 6 rectangle for example.
There is a square that has a length of 4. Area: 4 x 4: 16 Perimeter: 4+4+4+4= 16 Yes, there is a shape with the same perimeter and area.
A 5 by 3 rectangle
Yes but not a square (or rectangle). A quadrilateral with an area of 16 sq units must have sides of at least 4 units and so a perimeter of at least 16 units. However, a circle of perimeter 15 units will enclose an area of 17.905 sq units (to 3 dp) so an ellipse of 15 units' perimeter will meet the requirements.
A square 4 squares in the middle and 4 lines out so it has to be a square!!! actually a square does not have the same perimeter and area a 4x4 area square has 8 perimeter so no squares do not but i have made a shape that has 32 perimeter and 32 area so it is possible and we don't want to tell you what the shape is. i already gave you too much information with the 32.... << inccorect A 4x4 square does have the same perimeter and area 4x4=16 4+4+4+4=16 But there are also other shapes such as a circle witha diameter of 2 A right angled triangle with sides of 6, and 8 and the hypotenuse being 10 has the same area as perimeter.
Oh, what a happy little question! Let's think about shapes that could have a perimeter of 15 and an area of 16. One shape that comes to mind is a rectangle with dimensions 4 by 4. Another possibility is a square with sides of length 4. These shapes show us that there can be different ways to create beautiful combinations of perimeter and area.
The shape that has an area of 12 and a perimeter of 16 is a rectangle. To find the dimensions of the rectangle, you can set up equations using the formulas for area and perimeter. Let the length of the rectangle be L and the width be W. The equations would be: 2L + 2W = 16 (perimeter) and LW = 12 (area). Solving these equations simultaneously will give you the dimensions of the rectangle.
4x4 square: perimeter - 16 area - 16 6x2 rectangle perimeter - 16 area - 12
The perimeter of each tile is 4 inches. So the perimeter of 16 tiles - separately - is 4*16 = 64 inches. The perimeter of a 16-tile shape depends on the shape.
Sometimes. Experiment with a small square and with a large square (though any shape rectangle will do). A square of 4 x 4 has a perimeter of 16, and an area of 16. A smaller square has more perimeter than area. A larger square has more area than perimeter.
A shape is a nebulous term. It may mean a triangle, a square, or a pentagon in 2D, or a block or pyramid in 3D etc. The perimeter and area cannot be found without defining the shape first. How many dimensions? How many sides? For example, if the shape is a square, which has 4 edges, its perimeter = 4 * 4 [m] = 16 [m] and its area = 4 [m] * 4 [m] = 16 [m^2].