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If the order of the roll matters (i.e. you start with die #1, roll it and record it's number, then do die #2, and so on), then the answer would be 65.
If the order of the roll does not matter (i.e. rolling 1, 2, 3, 4, 5 is considered the same as rolling 5, 4, 3, 2, 1), then the answer is 434. This is equal to:
(d + (f - 1))! / (d! * (f - 1)!)
Where 'd' is the number of dice used and 'f' is number of faces on each die. There may be a more formal definition as I just worked out that one myself.
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5 dice each dice has 6 numbers how many combinations could be?
163759438475047695685695034395784593850835943859458474836937657 i have just tried it
4 dice each dice has 6 numbers how many combinations could there be?
Oh, dude, you're hitting me with some math here. So, if you have 4 dice, each with 6 numbers, you would have 6^4 possible combinations. That's like 1,296 different ways those dice could land. So, you better start rolling if you want to try them all!
How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many combinations can you make using numbers 1 through to 10 each with three different numbers?
1000
