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Add 12 to each side: 4x + 6x = 20 ie 10x = 20 so x = 2
8 + y = 4x8 + y - 4x = 4x - 4x 8 + y - 4x = 0 8 - 4x + y = 0
If the equation is y = 4x + 8, then the standard form is 4x - y + 8 = 0
Lets simplify the above given equation : -8 plus 6(-x - 3) plus 4x simplified as : -8-6x -18 +4x =-2x -26 . =-2(x+13).
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
4x + 8 + 7x + 12 = 11x + 20
If: 4x+(-12) = 8 then 4x = 20 and x = 5
x=3
8+7x = 20+3x 7x-3x = 20-8 4x = 12 x = 3
y = 2x^(2) + 4x + 8 dy.dx = 2(2)x^(2-1) + 4x^(1-1) +8x^(0) dy/dc = 2(2)x^(1) + (1)4x^(0) + (0)8x^(0-1) dy/dx = 4x + 4 + 0 dy/dx = 4x + 4 *The derivative). NB #1 The original index number becomes a coefficient ( in brackets). Then subtract '1' from the original index value, for the new index value. #2 Any term raised to the power of '0' = 1. #3 Any term multiplied by '0' = 0.
i thinking this answer should be -20
Add 12 to each side: 4x + 6x = 20 ie 10x = 20 so x = 2
4x - 8 = 12 + 6x 4x - 6x = 12 + 8 -2x = 20 -x = 20/2 x = -10 Check: 4(-10) - 8 = 12 + 6(-10) -40 - 8 = 12 + -60 -48 = -48
2(4x + 4) = (4x - 12) 8x + 8 = 4x - 12 8x - 4x + 8 = 4x - 4x - 12 4x + 8 = -12 4x + 8 - 8 = -12 - 8 4x = -20 4x/4 = -20/4 x = -5
-4x - 8 = -2x + 12Add 4x to each side:-8 = 2x + 12Subtract 12 from each side:-20 = 2xDivide each side by 2:-10 = x
4x+8
Find the value of 'x' when 2x+8=4x+20 First subtract '2x' from both sides. 8=2x+20 Then subtract '20' from each side. -12=2x Then divide each side by '2' -6=x. Therefore 'x=-6'