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656

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Olivia Zeng

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1y ago
This answer is:
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Anonymous

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3y ago

585

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Anonymous

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3y ago
its not 585 because they don't add up to 17
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Laurel Hoffman

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2y ago
not true

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Q: What 3 digit palindromic number has digits that add to 17 and multiply to 180?
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Related questions

How many 8 digit palindromic numbers are there?

a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)


What three digit number whose digits are all odd and different has a sum of the three digits that is palindromic?

137?


How many 3-digit palindromic numbers are there?

To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.


What is the sum of the digits of the largest 4-digit palindromic number which is divisible by 15?

-11


Is a 10 digit palindromic number bigger than a 11 digit palindromic number?

No.


What is smallest 4 digit palindromic number?

1001 is the smallest 4 digit palindromic number.


When you multiply a 3 digit number by a 2 digit number what is the greatest number of digits the product can have?

It can have up to 5 digits.


How do you generate 3-digit palindromic number?

Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.


What two digit number if you multiply the digits are larger than the number itself?

17 \


What is the maximum number of different three digit palindromes you can make using any digit?

There are 10 digits, but for a three digit number the first number cannot be a 0. Thus: there is a choice of 9 digits for the first (and last digit which must be the same), with 10 choices of digit for the second (middle) digit, making 9 × 10 = 90 such palindromic numbers.


Multiply the number 12345679 missing the digit 8 by any digit then multiply the result by 9 The result of this will be a number whose digits are all equal to the one you chose?

It works!


The lowest four-digit palindromic number?

1001