There are 10 digits, but for a three digit number the first number cannot be a 0.
Thus: there is a choice of 9 digits for the first (and last digit which must be the same), with
10 choices of digit for the second (middle) digit,
making 9 × 10 = 90 such palindromic numbers.
For there to be palindromes, each digit must be replicated. Therefore there are at most three distinct digits.If there are 3 pairs of different digits, then there are 6 palindromes. If there can be more duplicate digits, then there are 27 palindromes.
There are 90 four-digit palindromes
There is 90 four digit palindromes.
There are no four-digit perfect squares that are palindromes.
There are 10 3-digit odd palindromes that are divisible by five.
For there to be palindromes, each digit must be replicated. Therefore there are at most three distinct digits.If there are 3 pairs of different digits, then there are 6 palindromes. If there can be more duplicate digits, then there are 27 palindromes.
There are 90 four-digit palindromes
There is 90 four digit palindromes.
There are no four-digit perfect squares that are palindromes.
There are 90 four-digit palindromes
There are 900 6-digit palindromes.
There are 10 3-digit odd palindromes that are divisible by five.
Any, and every, number can be transformed into a palindrome.
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.
-1
Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
90