7 + 8 + 9 + 10 + 11 = 45
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7-8
The numbers are 76 23 45
To make 92 with consecutive numbers, you can use the formula for the sum of an arithmetic series: n/2 * (first number + last number) = 92. Since we are looking for consecutive numbers, the first number can be 45 and the last number can be 47. Plugging these values into the formula, we get 3/2 * (45 + 47) = 3/2 * 92 = 92, so the consecutive numbers 45, 46, and 47 add up to 92.
47
220