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For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
1, 2, 4, 5, 7, 8
It would be 9,992 since 1,249 * 8 = 9992. 1250 * 8 would equal 10,000 and this is not a 4 digit number, but a 5 digit number. The divisibility rule for 8 states that the last 3 digits of a number must be divisible by 8 and this is true as 992/8 = 124. Hopefully that helps.
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.