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Which digits should come in place of and if the no 62684 is divisible by both 8 and 5?
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
What four digit number is divisible by 8 but not 2 3 4 5 6 7 or 9?
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
The number 7000 is divisible by which single digit numbers?
1, 2, 4, 5, 7, 8
What is the largest 4 digit number divisible by 8?
It would be 9,992 since 1,249 * 8 = 9992. 1250 * 8 would equal 10,000 and this is not a 4 digit number, but a 5 digit number. The divisibility rule for 8 states that the last 3 digits of a number must be divisible by 8 and this is true as 992/8 = 124. Hopefully that helps.
What is the rule for a number that is divisible by 4?
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.
What is the smallest 5 digit number divisible by 23456910?
There is no 5 digit number which is divisible by 23456910 (an 8-digit number)..
What is a 4 digit number that is divisible by 5 and 8?
1000.
What is the greatest 5 digit number that is divisible by 8?
It is 99992.
What 4 digit number divisible by 5 and 8?
4000
What is a 8 digit number that is divisible by 5 and 6?
30,000,000
Is 678 divisible by 5?
No, 678 is not divisible by 5 because the last digit is 8, and for a number to be divisible by 5, the last digit must be either 0 or 5.
What is a four digit number that is divisible by 3 5 and 8?
1200 = 3*5*8*10
Which digits should come in place of and if the no 62684 is divisible by both 8 and 5?
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
When four digit number A 5 5 B is divisible by 36 What is the sum of A and B?
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
Is 141 divisible by 8?
No. All multiples of 8 are even, but 141 is odd, so 141 is not divisible by 8. ------------------------------------------ To test if a number is divisible by 8, add 4 times the hundreds digit to 2 times the tens digit to the ones digit; if this sum is divisible by 8, then so is the original number. The test can be repeated on the sum, so continue the summing process until a single digit remains - only if this single digit is an 8 is the original number divisible by 8. 141 → 4 × 1 + 2 × 4 + 1 × 1 = 13 13→ 4 × 0 + 2 × 1 + 3 = 5 5 is not 8, so 141 is not divisible by 8 141 ÷ 8 has a remainder of 5.
What four digit number is divisible by 8 but not 2 3 4 5 6 7 or 9?
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
Is the number 26 divisible by 2 3 5 or 9 How do you know?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.
