1 x 26, 2 x 13, 13 x 2, 26 x 1.
650 = 26 x 25 = 26 x 5 (squared ) 260 = 26 x 10 = 26 x (5 x 2) 104 = 26 x 4 = 26 x 2 (squared) 104 = 26 x (2x2) 104 = 26 x 2 (squared) 104 = 26 x (2x2) 650 260 104 104 104 104
26 x 26 = 26^(2) = 676 or 26 has the factors 2 & 13. so we can multiply 13 x 13 = 169 169 x 2 = 338 338 x 2 = 676 Or Long Multiplication 26 X 26 260 ( That is 26 X 10 ) 260 ( that is 26 x 10 again , making 20). 156 ( that is 26 x 6 = ) = 676 ===== or 26 x26 ===== 520 (26 X 20 = 520) 156 676 ====
26 - x = xAdd 'x' to both sides.26 = 2xDivide both sides by 2.13 = x
Let the required number be x. According to question: When x is added to -26 we get 14. Therefore, x + (-26) = 14 x - 26 = 14 x = 14 + 26 = 40. So, 40 must be added to -26 to get 14.
x2 = (26 + x)2 Taking square roots: x = +/-(26 + x) Then x = 26 + x or x = -26 -x The first gives a nonsense "equation" 0 = 26 but the second gives 2x = -26 or x = -13
1 x 26, 2 x 13, 13 x 2, 26 x 1.
26 * x = 15 x = 15/26 x = .5769 or 57.69%
This is easiest to answer by working out the probability of not getting such a license plate and subtracting that from 1. There are 10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10 different possible license plates (since there are 10 digits: 0-9 and 26 letters: A-Z). To not have any repeated digits or letters, there are: 10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9 possible license plates (since the two digits must be different and the seven letters must all be different). Meaning the probability of getting one of these is: (10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9)/(10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10) = (25 x 3 x 23 x 11 x 21 x 9)/(26 x 13 x 13 x 13 x 13 x 13) = 3586275/9653618 ⇒ probability of getting at least one repeating digit or number is: 1 - 3586275/9653618 = 6067343/9653618≈ 0.629
1 x 26, 2 x 13, 13 x 2, 26 x 1.
26 = 1 x 26, 2 x 13, 13 x 2, 26 x 1
650 = 26 x 25 = 26 x 5 (squared ) 260 = 26 x 10 = 26 x (5 x 2) 104 = 26 x 4 = 26 x 2 (squared) 104 = 26 x (2x2) 104 = 26 x 2 (squared) 104 = 26 x (2x2) 650 260 104 104 104 104
405600. Six possible variations of 2 letters (L) and 2 digits (D): LLDD would be 26 x 26 x 10 x 10 = 67600 LDLD would be 26 X 10 X 26 X 10 = 67600 LDDL would be 26 X 10 X 10 X 26 = 67600 DLDL would be 10 x 26 x 10 x 26 = 67600 DLLD would be 10 x 26 x 26 x 10 = 67600 DDLL would be 10 x 10 x 26 x 16 = 67600 6 x 67600 = 405600
26 x 26 = 26^(2) = 676 or 26 has the factors 2 & 13. so we can multiply 13 x 13 = 169 169 x 2 = 338 338 x 2 = 676 Or Long Multiplication 26 X 26 260 ( That is 26 X 10 ) 260 ( that is 26 x 10 again , making 20). 156 ( that is 26 x 6 = ) = 676 ===== or 26 x26 ===== 520 (26 X 20 = 520) 156 676 ====
1, 2, 13 and 26 as follows:1 x 26, 2 x 13, 13 x 2, 26 x 1
26 = 1 x 26 or 2 x 13. Factors of 26: 1, 2, 13, 26. Prime factorization: 26 = 2 x 13
26 - x = xAdd 'x' to both sides.26 = 2xDivide both sides by 2.13 = x