The sum of three consecutive integers is -72
Let the two consecutive integers be n and n+1. Then, n + (n + 1) < 55 2n + 1 < 55 2n < 55 - 1 : 2n < 54 n < 27 The Inequality Statement can therefore be modified to show that for two consecutive integers to be less than 55 then the smaller integer must be less than 27.
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The answer is, obviously, 9.
156 and 158 sum to 314.
There are only 3 sets of consecutive even integers less than 12, you can work it out...
The sum of three consecutive integers is -72
The integers are 5 and 7.
The first integer is 17.
a+(a+1)+(a+2) = (a+1)-163a+3 = a-152a = -18a = -9(a+1) = -8The middle integer is -8.
The sum is four.
It depends, if a number with positive integers is greater than the number with the negative integer therefore the sum will be in positive integer. And if the number with positive integer is less than the number with the number with negative integer then the sum will be in negative integer.
It can be.
Let the two consecutive integers be n and n+1. Then, n + (n + 1) < 55 2n + 1 < 55 2n < 55 - 1 : 2n < 54 n < 27 The Inequality Statement can therefore be modified to show that for two consecutive integers to be less than 55 then the smaller integer must be less than 27.
The smaller integer is 17.
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