a+(a+1)+(a+2) = (a+1)-16
3a+3 = a-15
2a = -18
a = -9
(a+1) = -8
The middle integer is -8.
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
-1, 1 and 3
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
The sum of three consecutive integers is -72
9,11,13
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
Middle integer must be a third of 93 so integers are 30, 31 and 32.
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
-1, 1 and 3
Let x be the middle integer: 3(x+1) = 7(x-1) 3x + 3 = 7x - 7 3x + 10 = 7x 10 = 4x So the middle one is 10/4 which is not an integer. So there is really no solution.
Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
The following is an example of consecutive integer problems.Example 1: Consecutive Integer ProblemThe sum of the least and greatest of 3 consecutive integers is 60. What are the values of the 3 integers?Solution:Step 1: Assign variables : Let x = least integer x+ 1 = middle integer x + 2 = greatest integerTranslate sentence into an equation.Sentence: The sum of the least and greatest is 60.Rewrite sentence: x + (x + 2) = 60Step 2: Solve the equationCombine like terms 2x + 2 = 60Isolate variable x2x =58Step 3: Check your answer 29 + 29 + 2 = 60The question wants all the 3 consecutive numbers: 29, 30 and 31Answer: The 3 consecutive numbers are 29, 30 and 31.pato c napano