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Write the sum of three consecutive integers using l where l the middle integer of the three?
The sum of three consecutive integers can be expressed using ( l ) as the middle integer. The three integers can be represented as ( (l-1) ), ( l ), and ( (l+1) ). Therefore, the sum is ( (l-1) + l + (l+1) = 3l ).
Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
What are the 4 consecutive odd integers where the sum of the middle two integers is equal to 24?
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
Find three consecutive odd integers such that three times the middle integer is one more than the sum of the first and third?
-1, 1 and 3
The sum of the three consecutive integers?
The sum of three consecutive integers is -72
Find three positive consecutive odd integers such that the square of the middle integer increased by four times the largest integer is 173?
9,11,13
Write the sum of three consecutive integers using l where l the middle integer of the three?
The sum of three consecutive integers can be expressed using ( l ) as the middle integer. The three integers can be represented as ( (l-1) ), ( l ), and ( (l+1) ). Therefore, the sum is ( (l-1) + l + (l+1) = 3l ).
Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
3 consecutive integeres whose sum is 93?
Middle integer must be a third of 93 so integers are 30, 31 and 32.
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
What are the 4 consecutive odd integers where the sum of the middle two integers is equal to 24?
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
Find three consecutive odd integers such that three times the middle integer is one more than the sum of the first and third?
-1, 1 and 3
There are 3 consecutive integers 3 times the largest is 7 times the smallest what are the integers?
Let x be the middle integer: 3(x+1) = 7(x-1) 3x + 3 = 7x - 7 3x + 10 = 7x 10 = 4x So the middle one is 10/4 which is not an integer. So there is really no solution.
The sum of 4 consecutive integers is 182 What is the first integer?
Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
What is three consecutive even integers whose sum equals 210?
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
What is the product of 15 consecutive integers whose average is7?
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
