82, 84, 86, 88
258/3 = 86 so the answer has to be 84+86+88
344/4 = 86, so integers are 83, 85, 87 and 89.
n + 2(n+1) + 3(n+2) = 86 n + 2n + 2 + 3n + 6 = 86 6n = 86 - 2 - 6 6n = 78 n = 13 Three consecutive integers are = 13,14,15
If two consecutive numbers add up to 86 then we can set up an equation like this: x=the first number So it makes sense that x+2=the second number (since the numbers are consecutive) And you know the sum of the two is 86. So the resulting equation is (x) + (x+2) = 86 => 2x + 2 = 86 2x = 84 x = 42 So the two numbers are 42 and 44.
The numbers are 82, 84, 86 and 88.
82, 84, 86, 88
85 & 86 85 & 86
258/3 = 86 so the answer has to be 84+86+88
84+86=170
344/4 = 86, so integers are 83, 85, 87 and 89.
n + 2(n+1) + 3(n+2) = 86 n + 2n + 2 + 3n + 6 = 86 6n = 86 - 2 - 6 6n = 78 n = 13 Three consecutive integers are = 13,14,15
86
20, 21, 22, 23
If two consecutive numbers add up to 86 then we can set up an equation like this: x=the first number So it makes sense that x+2=the second number (since the numbers are consecutive) And you know the sum of the two is 86. So the resulting equation is (x) + (x+2) = 86 => 2x + 2 = 86 2x = 84 x = 42 So the two numbers are 42 and 44.
I assume you wish to know which four consecutive even integers sum to 340. Let the smallest of the integers be x. Then the others are x+2, x+4 and x+6 and x + (x+2) + (x+4) + (x+6) = 340 iff 4x = 328 iff x = 82. So the integers are 82, 84, 86 and 88.
85, 86, 87