There are infinitely many possible rectangles.
Let A be ANY number in the range (0,6] and let B = 12-A.
Then a rectangle with width A and length B will have a perimeter of 2*(A+B) = 2*12 = 24 units.
Since A is ANY number in the interval (0,6], there are infinitely many possible values for A and so infinitely many answers to the question.
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Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
Yes, it can because a 3 by 6 rectangle has the perimeter of 18 and has the area of 18! :)
To find the perimeter of a rectangle, you add up all the sides. In this case, the room is 24 feet long and 15 feet wide. So, the perimeter would be 24 + 24 + 15 + 15 = 78 feet.
No. Here are four rectangles with the same perimeter:1 by 6 . . . . . perimeter = 14, area = 62 by 5 . . . . . perimeter = 14, area = 103 by 4 . . . . . perimeter = 14, area = 1231/2 by 31/2 . . perimeter = 14, area = 121/4With all the same perimeter . . . -- The nearer it is to being square, the more area it has.-- The longer and skinnier it is, the less area it has. If somebody gives you some wire fence and tells you to put it uparound the most possible area, your first choice is to put it up ina circle, and your second choice is to put it up in a square. Rectanglesare out, if you can avoid them.