Add all the sums, then divide by the number of sums. (ie. the average.)
Partial sums for a sequence are sums of the first one, first two, first three, etc numbers of the sequence. So, the series of partial sums is:2, 6, 14, 30, 62, ...It is the sequence whose nth term isT(n) = 2^(n+1) - 2 for n = 1, 2, 3, ...
you can make at least 25 sums
Well, 1 is equal to 1. 9 is equal to 9. So any number from 0 to 9. I do not think this is what is meant by the question. If you mean any number with more than one digit. There is no such number. Because 11 sums to 2. 19 sums to 10. 21 sums to 3. 29 sums to 11. 111 sums 3. 119 sums to 11. The sums do not grow as fast the increase of digits.
180x(N-2)(interior angle) All polygon of the sums of exterior angles is 360. (if convex)
No.
all the sums are 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,and 24
Emily worked out all the sums mentally.
Add all the sums, then divide by the number of sums. (ie. the average.)
No.
156
No, none of them do.
360
The team of researchers which is writing up a report sums them up.
9...7 + 6 + 14 = 27 divided by 3 (number of sums) = average I would hope this is a joke
As vector sums, the answer is 19 8 14
Not all people will find the same sums hard. Also, when you are older you may well find that sums that look hard now are really quite easy.