Oh, dude, you can divide 20 into equal groups in so many ways! Like, you could do 4 groups of 5, 5 groups of 4, 10 groups of 2, or even 20 groups of 1. It's like a math buffet, pick your favorite combo!
Yes you can, but you have to use zig zag lines. Using straight lines there are only four ways to divide a square into two equal parts (along the lines of symmetry).
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
In complete sentnces, explain why you can cut the rectangles into different shapes and still have four equal parts.
30
To divide 52 evenly into groups, you would need to find the factors of 52. The factors of 52 are 1, 2, 4, 13, 26, and 52. Therefore, you can divide 52 evenly into groups in 6 ways: (1, 52), (2, 26), (4, 13), (13, 4), (26, 2), and (52, 1).
divide a square into eighths
Yes you can, but you have to use zig zag lines. Using straight lines there are only four ways to divide a square into two equal parts (along the lines of symmetry).
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
In complete sentnces, explain why you can cut the rectangles into different shapes and still have four equal parts.
three
30
6 ways. 32 divided by 1=32 32 divided by 2=16 32 divided by 4= 8 32 divided by 8 = 4 32 divided by 16= 2 32 divided by 32= 1
To divide 52 evenly into groups, you would need to find the factors of 52. The factors of 52 are 1, 2, 4, 13, 26, and 52. Therefore, you can divide 52 evenly into groups in 6 ways: (1, 52), (2, 26), (4, 13), (13, 4), (26, 2), and (52, 1).
6 and 6
You can have one group of 12, two groups of 6, three groups of 4, four groups of 3, six groups of 2, or twelve groups of one. If you count "one group of 12", then there are six different ways. If not, then there are five. To be awkward, the way the question is put, there is an infinity of ways. Choose any n, where n is any positive integer number you like and you can have n groups each one with 12/n in it.
5
18 groups of 4