There are 166 multiples in 500 (500/3=166r2)and 33 multiples in100(100/3=33 r1) if you subtract the later from the first.... 166-33=133
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
The multiples of 3 up to 30 are: 3,6,9,12,15,18,21,24,27,30.The multiples of 5 up to 30 are: 5,10,15,20,25,30.The only common multiples are 15 and 30.The LCM is: 30
the multiples of 25 between 1 and 500 are 25,50 ,75,100,125,150,175,200,225,250,275,300,325,350,375,400,425,450,475, & 500
Oh, dude, multiples of 4 up to 500? That's like, easy peasy. So, you just start at 4, then add 4, then add 4, and keep going until you hit 500. It's like a never-ending party of numbers: 4, 8, 12, 16, and so on until you reach 500. Enjoy the multiples ride!
There are 166 multiples in 500 (500/3=166r2)and 33 multiples in100(100/3=33 r1) if you subtract the later from the first.... 166-33=133
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
just count by 3's upto 500. For Example: 3, 6, 9, 12, 15, 18, 21, 24, etc.....upto 500
There are 500 multiples of 12 in that range.
The multiples of 3 up to 50 are: 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48
There are no multiples of 500 in 100.
500 contains 50 multiples of 10.
All multiples of 3 have digits that add up to a multiple of 3.
The multiples of 3 up to 30 are: 3,6,9,12,15,18,21,24,27,30.The multiples of 5 up to 30 are: 5,10,15,20,25,30.The only common multiples are 15 and 30.The LCM is: 30
the multiples of 25 between 1 and 500 are 25,50 ,75,100,125,150,175,200,225,250,275,300,325,350,375,400,425,450,475, & 500
Multiples of 3 are easy to identify. Their digits add up to a multiple of 3.
Oh, what a happy little question! To find the sum of the first 500 multiples of 3, we can use the formula for the sum of an arithmetic series: (n/2) * (first term + last term). In this case, the first term is 3 and the last term is 3 * 500. Plugging these values in, we get (500/2) * (3 + 1500) = 250 * 1503 = 375,750.