8 if them with a remainder of 2
-6s+10 = -5s 5s-6s = -10 -s = -10 s = 10
6/6 +6/6=2
20.
Depends what you mean by "sixes".There are 2 possible answers:9 - There is six, twenty six, thirty six, ..., ninety six.20 - There are the 6s at the end of 6, 16, 26, ..., 96 and the 6s at the beginning of 60, 61, ..., 69.
if there is only 1 6 your chances r 1 to 6
The 6s sublevel can hold a maximum of 2 electrons.
(s + 6)(6s - 7)
13s - 2
76 and 1/2 of them.
4 6s = 4*6 = 24. As a fraction, this can be written as 24/1.
16
-40 = 8-6s -40 - 8 = 6s -48 = 6s 8 = s
The answer, using the Binomial distribution is 100C5*(1/6)5*(5/6)95 = 0.000291 (approx).
Ceseum, 55Cs, has just 1 '6s' electron: 2, 8, 18, 18, 8, 1 electrons in the 1st to 6st shell respectevely.
4/6 = 2/3
8 if them with a remainder of 2